1 solutions

  • 0
    @ 2024-11-6 22:39:43

    感觉是不是没啥讲的必要了。

    直接根据题意分讨即可?

    void solve()
    {
        _clear();
    	cin>>n;
    	A=10;
    	if(n>=30)
    		A+=min(30ll,n-30);
    	if(n>=60)
    		A+=(n-60)*2;
    	if(n<=48)
    		B=0;
    	else
    		B=(n-48)*2;
    	if(A<B)
    		cout<<"A "<<B-A<<endl;
    	else
    		cout<<"B "<<A-B<<endl;
    }
    
    • 1

    [CZOJ 一周一测 R17 A] 送分题 1(阿瓦的流量)

    Information

    ID
    1225
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    39
    Accepted
    12
    Uploaded By